If it's not what You are looking for type in the equation solver your own equation and let us solve it.
5x^2+41x-12=0
a = 5; b = 41; c = -12;
Δ = b2-4ac
Δ = 412-4·5·(-12)
Δ = 1921
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(41)-\sqrt{1921}}{2*5}=\frac{-41-\sqrt{1921}}{10} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(41)+\sqrt{1921}}{2*5}=\frac{-41+\sqrt{1921}}{10} $
| 32w^2-18=0 | | 37=-3+5(x=6 | | 23+n=40 | | 0.6x+0.3=0.3x+0.6 | | 1900x+150=1400+275 | | 3/4n+8=1/4n+1 | | 3/4n+8=1/4n+4 | | x=46+3/4 | | -9=6m+15 | | 12n-3=63 | | (5x-213)+(3x+19)=180 | | -7x-4=-8x+2 | | -7x-4=8x+2 | | (-6-5i)-(2-I)=0 | | 8d-5(6d+2)-12=9d | | 21.4+w=56.9 | | 0.5y-2=0.4y+0.2 | | 2^x=1025 | | 5x-14+3x-2=180 | | 0.25(4m+-8)+14m=-12 | | 5x+26=12x-2 | | 2*x+8=2(4+x) | | 3^x=0.1 | | 5x+3X+4X=12 | | 1/y-1-4/y-4=0 | | 3(5^2x-1)-2=373 | | 4e+6e=4(5)2 | | 2v-6=-(6-5v)+4v | | 9x-3+6x=8x+9 | | y/3-8=0y= | | 2x+5=13x | | 8x-14=3(3x+3) |